This may be more of a question on TrueType fonts than VBA, but here goes!
The following will replace a selected character with an "a"
sh.Text.Story.Text = ChrW(&H41)
but what I really need to do is: if the letter is a lowercase letter, replace it with a "stylized" replacement character whose unicode values start at &hF000.
I can tell you what doesn't work, so that may make it clearer as to what I want to do
sh.Text.Story.Text = ChrW(&H41+&HEF9F) ' (&hF000 - &h41) =&HEF9F
Possibly it is significant to say that CHARMAP shows the starting, stylized set begins at &hF000 and labels that as "Private Use"
ChrW(&H41) is actually a captial "A". The lower case "a" whould be ChrW(&H61)
Stylized Sets are an OpenType Feature. So you will need to set the feature for this to work. Here is a quick example.
Using the font "Arial" type the letter A, select it, and in the VBA Immediate window type:
ActiveShape.Text.Story.Text = ChrW(&H36)
The "A" should now be a "6"
Now lets used the Sylized version of this. Keep your "6" selected and in the VBA Immediate window type:
ActiveShape.Text.Story.SetOpenTypeFeature "ss03", 1
You should see it change. Here are the two versions:
I was able to see what Stylistic Set the character belongs too by using the Glyphs Docker
I was able to get the Open Type Feature String "ss03" by looking it up here:
OpenType Registered Features
The 1 turns the feature on, if you wanted to turn it off and go back to the stardard "6" select the character again and in the VBA Immediate window type:ActiveShape.Text.Story.SetOpenTypeFeature "ss03", 0
Hopefully that all helps. All testing I did for this was in CorelDRAW 2022, I did not have time to test previous versions.
Extremely helpful. Thanks kindly.