Remove double lines macro

I have double cut lines when I "Trim" one shape from another. Where the two objects meet each other it cuts both lines even though they are identical and in the same place. This shreds my sandblast resist stencil that i am cutting. I installed RemoveUnderlyingDups.gms and when I try to use it i get a -Microsoft Visual Basic RunTime error '424' Object Required- message. When I hit the debug button it shows me the code error. i have copied it and pasted below. Please help as I know nothing about macros or codes. I've been lucky to get this far via google searches and youtube videos. The error is occurring in line 16 (shown in RED)

Public Sub boostStart(Optional ByVal unDo As String = "") ' =================================================================================================
If unDo <> "" Then ActiveDocument.BeginCommandGroup unDo
Optimization = True
EventsEnabled = False
ActiveDocument.PreserveSelection = False
End Sub

Public Sub boostFinish(Optional ByVal endUndoGroup As Boolean = False) ' =================================================================================================
Dim cs As Object
ActiveDocument.PreserveSelection = True
EventsEnabled = True
Optimization = False
Set cs = CorelDRAW.CorelScript
If endUndoGroup Then ActiveDocument.EndCommandGroup
End Sub

Sub removeUnderlyingDups()
Dim s As Shape, sr As New ShapeRange, props() As Double
Dim toDEL As New ShapeRange, stat As AppStatus, Jitter As Double, cnt&, idx&, _
x As Double, y As Double, w As Double, h As Double, n&, match%, i&
Jitter = 0.0001
If ActiveSelectionRange.Count = 0 Then Set sr = ActivePage.FindShapes _
Else Set sr = ActiveSelectionRange.Shapes.FindShapes
If sr.Count = 0 Then Exit Sub
ReDim props(1 To sr.Count, 1 To 5): cnt = 0: idx = 0
Set stat = Application.Status
stat.BeginProgress "Looking for curve duplicates...", True
For Each s In sr
idx = idx + 1: stat.Progress = idx / sr.Count * 100
If stat.Aborted Then Exit For
x = s.PositionX: y = s.PositionY: n = s.Curve.Nodes.Count
w = s.SizeWidth: h = s.SizeHeight: match = False
If w < Jitter And h < Jitter Then
toDEL.Add s: cnt = cnt + 1
For i = 1 To cnt
If stat.Aborted Then Exit For
If Abs(props(i, 1) - x) < Jitter Then _
If Abs(props(i, 2) - y) < Jitter Then _
If Abs(props(i, 3) - w) < Jitter Then _
If Abs(props(i, 4) - h) < Jitter Then _
If props(i, 5) = n Then _
toDEL.Add s: match = True: Exit For
Next i
If Not match Then
cnt = cnt + 1: props(cnt, 1) = x: props(cnt, 2) = y
props(cnt, 3) = w: props(cnt, 4) = h: props(cnt, 5) = n
End If
End If
Next s
If toDEL.Count = 0 Then Exit Sub
If MsgBox("Confirm delete " + CStr(toDEL.Count) + " objects", vbOKCancel) = vbOK Then _
End Sub

Public Sub NodeClean2()
Dim s As Shape, s2 As Shape
Dim n As Node, n2 As Node, o As Node, o2 As Node, IsFirstNode As Boolean
Dim origShapes As New ShapeRange, nearShapes As ShapeRange
Dim combineShapes As New ShapeRange, delShape As New ShapeRange, Alone%

Set origShapes = ActivePage.FindShapes(, cdrCurveShape)
boostStart "Node cleaning"
On Error GoTo CloseUndoTransaction
Do While origShapes.Count > 1
Set s = origShapes(1)
With s.Curve.SubPaths.Item(1): Set n = .StartNode: Set o = .EndNode: End With

Set nearShapes = ActivePage.SelectShapesAtPoint(n.PositionX, n.PositionY, True).Shapes.All
nearShapes.AddRange ActivePage.SelectShapesAtPoint(o.PositionX, o.PositionY, True).Shapes.All
Alone = (nearShapes.Count = 1)

Do While nearShapes.Count > 0
Set s2 = nearShapes(1)
If s2.Type = cdrCurveShape And s2.StaticID <> s.StaticID Then
With s2.Curve.SubPaths.Item(1): Set n2 = .StartNode: Set o2 = .EndNode: End With

If n.GetDistanceFrom(o2) = 0 Or o.GetDistanceFrom(o2) = 0 Then
IsFirstNode = (n.GetDistanceFrom(o2) = 0)
combineShapes.Add s: combineShapes.Add s2
delShape.RemoveAll: delShape.Add s2
origShapes.RemoveRange delShape
Set s = combineShapes.Combine: combineShapes.RemoveAll
With s.Curve.SubPaths
If .Count = 2 Then _
If IsFirstNode Then .Item(2).EndNode.JoinWith .Item(1).StartNode _
Else .Item(2).EndNode.JoinWith .Item(1).EndNode
End With
If s.Curve.Nodes.First.GetDistanceFrom(s.Curve.Nodes.Last) = 0 Then _
s.Curve.Nodes.First.JoinWith s.Curve.Nodes.Last
origShapes.Add s
Exit Do
End If
End If
nearShapes.Remove 1
origShapes.Remove 1

boostFinish True
If Err.Number Then MsgBox "Error: " + Err.Description
End Sub

  • In reply to Pioneer Rock:

    OK, I think I understand the nature of the problem better. When you trim one closed curve using another closed curve, the shared edges are "doubled up" for your cutting.

    You will get different results with the Trim operation if the "target" object is an open curve.

    Before, with two closed shapes:

    Convert the rectangle to curves, then break it so that it becomes an open curve. In this case, I've actually shown a visible gap, but that's not necessary; it's sufficient just to Break Apart a node to open the curve:

    Trim the open curve using the closed curve:

    Move the closed curve out of the way to see the result of the Trim:

    Is that the sort of result you are looking for?

  • In reply to Pioneer Rock:

    Pioneer Rock
    After reading more carefully what you wrote and breaking the curve it works great!!!!!!! Thank you! Thank you!

    Are you aware of any Macros that would do this automatically?

    You're welcome. I've never tried to accomplish this particular sort of task, so it was educational for me.

    I don't know exactly where one might go with automation on this.

    It is fairly quick (a few seconds)  to add a node (if necessary) then Break Apart to open the curve.

    If one uses the Shaping docker, it is already easy to select multiple shapes to use as "cutters", press the "Trim" button, and then select the "target" to be trimmed.

  • In reply to Eskimo:

    An added hint for others who might be facing this same issue with multiple (even dozens or hundreds) objects, it shortens the process immensely to COMBINE (Shift+Left click each object then OBJECT>COMBINE) all of the different objects that you want "punched out" of the background and do JUST ONE trim. Saves tons of time. Problem solved! Thanks again ESKIMO:)